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X-5/7X=1
We move all terms to the left:
X-5/7X-(1)=0
Domain of the equation: 7X!=0We multiply all the terms by the denominator
X!=0/7
X!=0
X∈R
X*7X-1*7X-5=0
Wy multiply elements
7X^2-7X-5=0
a = 7; b = -7; c = -5;
Δ = b2-4ac
Δ = -72-4·7·(-5)
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-3\sqrt{21}}{2*7}=\frac{7-3\sqrt{21}}{14} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+3\sqrt{21}}{2*7}=\frac{7+3\sqrt{21}}{14} $
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