X-5/x+6=x+1/x+4

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Solution for X-5/x+6=x+1/x+4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

X-(5/x)+6 = x+1/x+4 // - x+1/x+4

X-x-(5/x)-(1/x)-4+6 = 0

X-x-5*x^-1-x^-1-4+6 = 0

2*x^0-1*x^1-6*x^-1 = 0

(2*x^1-1*x^2-6*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-1*x^2-6*x^0) = 0

x^1

2*x-x^2-6 = 0

2*x-x^2-6 = 0

DELTA = 2^2-(-6*(-1)*4)

DELTA = -20

DELTA < 0

x in { } 

x belongs to the empty set

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