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X-5=4(2X+3)/3
We move all terms to the left:
X-5-(4(2X+3)/3)=0
We multiply all the terms by the denominator
X*3)-(4(2X+3)-5*3)=0
We add all the numbers together, and all the variables
X*3)-(4(2X+3)=0
Wy multiply elements
3X^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{0}{6}=0$
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