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X-5=4/3X
We move all terms to the left:
X-5-(4/3X)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+4/3X)-5=0
We get rid of parentheses
X-4/3X-5=0
We multiply all the terms by the denominator
X*3X-5*3X-4=0
Wy multiply elements
3X^2-15X-4=0
a = 3; b = -15; c = -4;
Δ = b2-4ac
Δ = -152-4·3·(-4)
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{273}}{2*3}=\frac{15-\sqrt{273}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{273}}{2*3}=\frac{15+\sqrt{273}}{6} $
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