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X-6=4/3X
We move all terms to the left:
X-6-(4/3X)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+4/3X)-6=0
We get rid of parentheses
X-4/3X-6=0
We multiply all the terms by the denominator
X*3X-6*3X-4=0
Wy multiply elements
3X^2-18X-4=0
a = 3; b = -18; c = -4;
Δ = b2-4ac
Δ = -182-4·3·(-4)
Δ = 372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{372}=\sqrt{4*93}=\sqrt{4}*\sqrt{93}=2\sqrt{93}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{93}}{2*3}=\frac{18-2\sqrt{93}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{93}}{2*3}=\frac{18+2\sqrt{93}}{6} $
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