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X-X2+42=0
We add all the numbers together, and all the variables
-1X^2+X+42=0
a = -1; b = 1; c = +42;
Δ = b2-4ac
Δ = 12-4·(-1)·42
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-13}{2*-1}=\frac{-14}{-2} =+7 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+13}{2*-1}=\frac{12}{-2} =-6 $
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