X.2(x+1)+3=-(2x+5)

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Solution for X.2(x+1)+3=-(2x+5) equation: 



X.2(X+1)+3=-(2X+5)

We move all terms to the left:

X.2(X+1)+3-(-(2X+5))=0

We multiply parentheses

X^2+X-(-(2X+5))+3=0



We calculate terms in parentheses: -(-(2X+5)), so:

-(2X+5)

We get rid of parentheses

-2X-5

Back to the equation:

-(-2X-5)



We get rid of parentheses

X^2+X+2X+5+3=0

We add all the numbers together, and all the variables

X^2+3X+8=0

a = 1; b = 3; c = +8;
Δ = b2-4ac
Δ = 32-4·1·8
Δ = -23
Delta is less than zero, so there is no solution for the equation

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