X.2(x+3)=8-3(x-4

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Solution for X.2(x+3)=8-3(x-4 equation: 



X.2(X+3)=8-3(X-4

We move all terms to the left:

X.2(X+3)-(8-3(X-4)=0

We multiply parentheses

X^2+3X-(8-3(X-4)=0



We calculate terms in parentheses: -(8-3(X-4), so:

8-3(X-4

determiningTheFunctionDomain
-3(X-4+8

Back to the equation:

-(-3(X-4+8)



We add all the numbers together, and all the variables

X^2+3X-(-3(X+4)=0



We calculate terms in parentheses: -(-3(X+4), so:

-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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-3(X+4





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