X.4(x-3)=2x+22

Solution for X.4(x-3)=2x+22 equation:

X.4(X-3)=2X+22

We move all terms to the left:

X.4(X-3)-(2X+22)=0

We multiply parentheses

X^2-3X-(2X+22)=0

We get rid of parentheses

X^2-3X-2X-22=0

We add all the numbers together, and all the variables

X^2-5X-22=0

a = 1; b = -5; c = -22;
Δ = b2-4ac
Δ = -52-4·1·(-22)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{113}}{2*1}=\frac{5-\sqrt{113}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{113}}{2*1}=\frac{5+\sqrt{113}}{2}
$