X.5(x+1)-3(2x+4)=4x-7

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Solution for X.5(x+1)-3(2x+4)=4x-7 equation:



X.5(X+1)-3(2X+4)=4X-7
We move all terms to the left:
X.5(X+1)-3(2X+4)-(4X-7)=0
We multiply parentheses
X^2+X-6X-(4X-7)-12=0
We get rid of parentheses
X^2+X-6X-4X+7-12=0
We add all the numbers together, and all the variables
X^2-9X-5=0
a = 1; b = -9; c = -5;
Δ = b2-4ac
Δ = -92-4·1·(-5)
Δ = 101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{101}}{2*1}=\frac{9-\sqrt{101}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{101}}{2*1}=\frac{9+\sqrt{101}}{2} $

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