X/(2x+1)=16/40

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Solution for X/(2x+1)=16/40 equation: 



X/(2X+1)=16/40

We move all terms to the left:

X/(2X+1)-(16/40)=0



Domain of the equation: (2X+1)!=0

We move all terms containing X to the left, all other terms to the right

2X!=-1

X!=-1/2

X!=-1/2

X∈R



We add all the numbers together, and all the variables

X/(2X+1)-(+16/40)=0

We get rid of parentheses

X/(2X+1)-16/40=0

We calculate fractions


40X/(80X+40)+(-32X-16)/(80X+40)=0

We multiply all the terms by the denominator


40X+(-32X-16)=0

We get rid of parentheses

40X-32X-16=0

We add all the numbers together, and all the variables

8X-16=0

We move all terms containing X to the left, all other terms to the right

8X=16

X=16/8

X=2

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