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(1/2)*x = (1/3)*x-1;x
x
3*y^3
(cos(x))^2
1/2-x = (1/2)*x;x
x
3;4;1;3;2;6
| f(x)=-x^2-12x+3 | | 4m=93 | | 3n+3=3.9 | | 16x-7=2X | | 12x^2y+18xy=0 | | 12=4xn | | cos(x+30)=cos(60-x) | | 12=3xn | | 6-2a+9= | | 2-7d=-74 | | 32=3x+12 | | 2^-3/2^-5 | | 9/8x7/8= | | 12=6xn | | 36=6-x | | 36=x-6 | | 3n-7=68 | | 6=3xn | | 36=6+x | | y=10*4/5-3 | | 2p=6(3p+2) | | 6=2xn | | tan(x)+1=sec(x) | | 36=x+6+x | | 4n-9=56 | | 9=3xn | | 143=12x+11 | | 8=4xn | | 36=6x+x | | 36=6x+c | | 10=2xn | | 2(t+8)-26= |