X/2(6-2x)+3x=4+2(5+x)

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Solution for X/2(6-2x)+3x=4+2(5+x) equation: 



X/2(6-2X)+3X=4+2(5+X)

We move all terms to the left:

X/2(6-2X)+3X-(4+2(5+X))=0



Domain of the equation: 2(6-2X)!=0

X∈R



We add all the numbers together, and all the variables

X/2(-2X+6)+3X-(4+2(X+5))=0

We add all the numbers together, and all the variables

3X+X/2(-2X+6)-(4+2(X+5))=0

We multiply all the terms by the denominator


3X*2(-2X+6)+X-((4+2(X+5)))*2(-2X+6)=0



We calculate terms in parentheses: -((4+2(X+5)))*2(-2X+6), so:

(4+2(X+5)))*2(-2X+6

We add all the numbers together, and all the variables

-2X+(4+2(X+5)))*2(+6

Back to the equation:

-(-2X+(4+2(X+5)))*2(+6)



We add all the numbers together, and all the variables

3X*2(-2X+6)+X-(-2X+(4+2(X+5)))*26=0

We add all the numbers together, and all the variables

X+3X*2(-2X+6)-(-2X+(4+2(X+5)))*26=0

Wy multiply elements

6X^2(--(-2X+(4+2(X+5)))*26+X=0

We use the square of the difference formula

6X^2(+(-2X+(4+2(X+5)))*26+X=0

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