X/2(x+3)-7x=18+5(x+4)

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Solution for X/2(x+3)-7x=18+5(x+4) equation: 



X/2(X+3)-7X=18+5(X+4)

We move all terms to the left:

X/2(X+3)-7X-(18+5(X+4))=0



Domain of the equation: 2(X+3)!=0

X∈R



We add all the numbers together, and all the variables

-7X+X/2(X+3)-(18+5(X+4))=0

We multiply all the terms by the denominator


-7X*2(X+3)+X-((18+5(X+4)))*2(X+3)=0



We calculate terms in parentheses: -((18+5(X+4)))*2(X+3), so:

(18+5(X+4)))*2(X+3



We add all the numbers together, and all the variables

X-7X*2(X+3)-((18+5(X+4)))*2(X+3)=0

Wy multiply elements

-14X^2(X-((18+5(X+4)))*2(X+3)+X=0

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