X/2-25=2(3/4x+8)

Solution for X/2-25=2(3/4x+8) equation:

X/2-25=2(3/4X+8)

We move all terms to the left:

X/2-25-(2(3/4X+8))=0


Domain of the equation: 4X+8))!=0

X∈R


We calculate fractions


4X^2/8X+()/8X-25=0

We multiply all the terms by the denominator


4X^2-25*8X+()=0

We add all the numbers together, and all the variables

4X^2-25*8X=0

Wy multiply elements

4X^2-200X=0

a = 4; b = -200; c = 0;
Δ = b2-4ac
Δ = -2002-4·4·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-200}{2*4}=\frac{0}{8}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+200}{2*4}=\frac{400}{8}
=50
$