If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(-1/3)*e^((-x)^2)
(9*ln(x))/x
1/5-1 = 0
1/(4-(9*x))
(x-3)^2+(y+2)^2-(x+3)^2-(y-4)^2;(x+4)^2+(y-1)^2-(x+2)^2-(y+3)^2
| h(0)=-16t^2+96t | | -6(t-3)-(t+1)=9 | | 3-6=1-6 | | 2sin^3-sin^2x+2sinx-1=0 | | Y=1.67x+7 | | 24x1/7 | | 2x^3+13x^2+3x=0 | | 5y+9=2-2y | | 6y-24x=96 | | 2(v-4)+5v=-1 | | 4w+2(w+3)=24 | | 5r^2=180 | | 27=2u+5(u-3) | | X2/3x=180 | | (2x+30)+x+(x+10)=180 | | 180=9x-1 | | 12.50+x*0.15=23.90 | | 2/3*x=16 | | (x+30)+(x+10)=180 | | 3x^2+25x-5.7=0 | | (x)(.10)(1)+(2x)(.12)(1)=2890 | | 17(c+4)=476 | | (x+36)+x=90 | | X-17=7-10 | | 2+8(x-5)=6-9(x-2) | | 3x+17-1-4X=1-4x-9+8 | | -4+8=x-13 | | 0.19x+5.95=15.84 | | 0.19x+5.95=15.93 | | -7=-12-q | | 10X=8/3-4X=6X | | 0.55x+7=11.94 |