X/2x+8=8x-4=

Solution for X/2x+8=8x-4= equation:

X/2X+8=8X-4=

We move all terms to the left:

X/2X+8-(8X-4)=0


Domain of the equation: 2X!=0

X!=0/2

X!=0

X∈R


We get rid of parentheses

X/2X-8X+4+8=0

We multiply all the terms by the denominator


X-8X*2X+4*2X+8*2X=0

Wy multiply elements

-16X^2+X+8X+16X=0

We add all the numbers together, and all the variables

-16X^2+25X=0

a = -16; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-16)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-16}=\frac{-50}{-32}
=1+9/16
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-16}=\frac{0}{-32}
=0
$