X/2x=4x/80

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Solution for X/2x=4x/80 equation:



X/2X=4X/80
We move all terms to the left:
X/2X-(4X/80)=0
Domain of the equation: 2X!=0
X!=0/2
X!=0
X∈R
We add all the numbers together, and all the variables
X/2X-(+4X/80)=0
We get rid of parentheses
X/2X-4X/80=0
We calculate fractions
(-8X^2)/160X+80X/160X=0
We multiply all the terms by the denominator
(-8X^2)+80X=0
We get rid of parentheses
-8X^2+80X=0
a = -8; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-8)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-8}=\frac{-160}{-16} =+10 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-8}=\frac{0}{-16} =0 $

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