If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X/3(5X-7)=39
We move all terms to the left:
X/3(5X-7)-(39)=0
Domain of the equation: 3(5X-7)!=0We multiply all the terms by the denominator
X∈R
X-39*3(5X-7)=0
Wy multiply elements
X-117X(5=0
| 1/3x-4=11-5/6x | | 5x-25=8 | | 1/6f-3=11 | | t/8-7=(-3) | | 12+7b=4b+6 | | F(x)=17,x= | | 2(b-10)=18 | | 8x-4(x8)=8 | | 22k+70=17k-95 | | -9=-1+v4 | | 4(x-3)=-2(x-3) | | -2m-38=-94 | | x/66−3.7=11 | | 11x=-40+2x+4 | | 7x-3-8x=7-x | | 5x+4-2x=x+12 | | 4(x-3)+8=12 | | 5x+33=2x | | 4c+5=-23 | | -5=-8p+(-3) | | X^2-4.16x=-10 | | 2x+4=x5 | | 12=4(v-2)-6v | | 8n+7+-3n=88 | | 1/3(9x-15)=-4+3x | | 0.22m-1.77=0.66m+1.33 | | -4(1-5x)=124 | | 2a-4=3a+2 | | -113=a+(-83) | | 2(3x-5)+4=36-12+x | | y+67=7 | | -32=4(3-3x)+4(x-3) |