X/3-1=(3/4)x+3

Solution for X/3-1=(3/4)x+3 equation:

X/3-1=(3/4)X+3

We move all terms to the left:

X/3-1-((3/4)X+3)=0


Domain of the equation: 4)X+3)!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X/3-((+3/4)X+3)-1=0

We calculate fractions


4X^2/12X+()/12X-1=0

We multiply all the terms by the denominator


4X^2-1*12X+()=0

We add all the numbers together, and all the variables

4X^2-1*12X=0

Wy multiply elements

4X^2-12X=0

a = 4; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·4·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*4}=\frac{0}{8}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*4}=\frac{24}{8}
=3
$