X/3x+42=2(3x+9

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Solution for X/3x+42=2(3x+9 equation: 



X/3X+42=2(3X+9

We move all terms to the left:

X/3X+42-(2(3X+9)=0



Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R



We multiply all the terms by the denominator


X-((2(3X+9)+42)*3X=0

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