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X/4X-10=6X-4
We move all terms to the left:
X/4X-10-(6X-4)=0
Domain of the equation: 4X!=0We get rid of parentheses
X!=0/4
X!=0
X∈R
X/4X-6X+4-10=0
We multiply all the terms by the denominator
X-6X*4X+4*4X-10*4X=0
Wy multiply elements
-24X^2+X+16X-40X=0
We add all the numbers together, and all the variables
-24X^2-23X=0
a = -24; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·(-24)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*-24}=\frac{0}{-48} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*-24}=\frac{46}{-48} =-23/24 $
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