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(3*x-1)/2+X/5 = (6*x+5)/4 // - (6*x+5)/4
(3*x-1)/2-((6*x+5)/4)+X/5 = 0
(3*x-1)/2+(-1*(6*x+5))/4+X/5 = 0
(4*5*(3*x-1))/(2*4*5)+(-1*2*5*(6*x+5))/(2*4*5)+(2*4*X)/(2*4*5) = 0
4*5*(3*x-1)-1*2*5*(6*x+5)+2*4*X = 0
8*X-70 = 0
(8*X-70)/(2*4*5) = 0
(8*X-70)/(2*4*5) = 0 // * 2*4*5
8*X-70 = 0
x belongs to the empty set
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