X/5-2(2x/5+1)=28

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Solution for X/5-2(2x/5+1)=28 equation: 


x in (-oo:+oo)

X/5-(2*((2*x)/5+1)) = 28 // - 28

X/5-(2*((2*x)/5+1))-28 = 0

X/5-2*((2*x)/5+1)-28 = 0

X/5-2*(2/5*x+1)-28 = 0

(-2*5*(2/5*x+1))/5+X/5+(-28*5)/5 = 0

X-2*5*(2/5*x+1)-28*5 = 0

X-4*x-140-10 = 0

X-4*x-150 = 0

(X-4*x-150)/5 = 0

(X-4*x-150)/5 = 0 // * 5

X-4*x-150 = 0

X-4*x-150 = 0 // - X-150

-4*x = -(X-150) // : -4

x = (-(X-150))/(-4)

x = (150-X)/(-4)

x = (150-X)/(-4)

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