X/5=(x+2)/9

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Solution for X/5=(x+2)/9 equation: 



X/5=(X+2)/9

We move all terms to the left:

X/5-((X+2)/9)=0

We calculate fractions


9X^2/()+(-((X+2)*5)/()=0



We calculate terms in parentheses: +(-((X+2)*5)/(), so:

-((X+2)*5)/(

We multiply all the terms by the denominator


-((X+2)*5)



We calculate terms in parentheses: -((X+2)*5), so:

(X+2)*5

We multiply parentheses

5X+10

Back to the equation:

-(5X+10)



We get rid of parentheses

-5X-10

Back to the equation:

+(-5X-10)



We get rid of parentheses

9X^2/()-5X-10=0

We multiply all the terms by the denominator


9X^2-5X*()-10*()=0

We add all the numbers together, and all the variables

9X^2-5X*()=0

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