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X/5X+4=1
We move all terms to the left:
X/5X+4-(1)=0
Domain of the equation: 5X!=0We add all the numbers together, and all the variables
X!=0/5
X!=0
X∈R
X/5X+3=0
We multiply all the terms by the denominator
X+3*5X=0
Wy multiply elements
X+15X=0
We add all the numbers together, and all the variables
16X=0
X=0/16
X=0
Równanie nie ma rozwiązania
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