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X/5X+4=3
We move all terms to the left:
X/5X+4-(3)=0
Domain of the equation: 5X!=0We add all the numbers together, and all the variables
X!=0/5
X!=0
X∈R
X/5X+1=0
We multiply all the terms by the denominator
X+1*5X=0
Wy multiply elements
X+5X=0
We add all the numbers together, and all the variables
6X=0
X=0/6
X=0
Równanie nie ma rozwiązania
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