X/5x=125x+2

Solution for X/5x=125x+2 equation:

X/5X=125X+2

We move all terms to the left:

X/5X-(125X+2)=0


Domain of the equation: 5X!=0

X!=0/5

X!=0

X∈R


We get rid of parentheses

X/5X-125X-2=0

We multiply all the terms by the denominator


X-125X*5X-2*5X=0

Wy multiply elements

-625X^2+X-10X=0

We add all the numbers together, and all the variables

-625X^2-9X=0

a = -625; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-625)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-625}=\frac{0}{-1250}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-625}=\frac{18}{-1250}
=-9/625
$