X/7=(3x+2)/20

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Solution for X/7=(3x+2)/20 equation: 



X/7=(3X+2)/20

We move all terms to the left:

X/7-((3X+2)/20)=0

We calculate fractions


20X^2/()+(-((3X+2)*7)/()=0



We calculate terms in parentheses: +(-((3X+2)*7)/(), so:

-((3X+2)*7)/(

We multiply all the terms by the denominator


-((3X+2)*7)



We calculate terms in parentheses: -((3X+2)*7), so:

(3X+2)*7

We multiply parentheses

21X+14

Back to the equation:

-(21X+14)



We get rid of parentheses

-21X-14

Back to the equation:

+(-21X-14)



We get rid of parentheses

20X^2/()-21X-14=0

We multiply all the terms by the denominator


20X^2-21X*()-14*()=0

We add all the numbers together, and all the variables

20X^2-21X*()=0

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