If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^3+x^2-8*x-12;x+2
ctg(x^(1/2))
-9/((x-4)^2) = 0;x
x
x*ln(x)
16-((1/2)*x^2)-(3*x)
| 3lx/10l=3 | | 3x+5y=46000 | | 4x^2-8y=0 | | 3x+57=46000 | | 3x-7=8-4x | | 7x+1+3x=2(5x+1) | | c2/3d^-5/c2/3d^-1 | | -8+7x=55 | | 1/3(6y-12)=2(y-2) | | -x+3(2x-5)=5 | | 1/5x-1/9x=4 | | 1/36y-12)=2(y-2) | | 0.5b-6.2=-9.8 | | 5k+12k+3k= | | 4+3y+5= | | 3/7×4= | | 68x=6596m | | 4(u+3)-7u=6 | | 3x-5(2x+3)=-1 | | 10=21-8(2-2w) | | (2x)(cosx)+x=0 | | 5(2x-7)-3(x+2)-17x= | | 9(x+4)=6(2x+4) | | 2x+y=3y+20 | | A(y-v)=x | | 1/8x-1/9x= | | 6-2(7-x)=56 | | 4(2x+3)=6(2-1) | | 5x^4-4x^5=.5 | | -15x+3=-2x+3 | | 8(x+w)=a | | 4x-3/6=3x-2 |