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X2+(2X+11)2=(3X+1)2
We move all terms to the left:
X2+(2X+11)2-((3X+1)2)=0
We add all the numbers together, and all the variables
X^2+(2X+11)2-((3X+1)2)=0
We multiply parentheses
X^2+4X-((3X+1)2)+22=0
We calculate terms in parentheses: -((3X+1)2), so:We get rid of parentheses
(3X+1)2
We multiply parentheses
6X+2
Back to the equation:
-(6X+2)
X^2+4X-6X-2+22=0
We add all the numbers together, and all the variables
X^2-2X+20=0
a = 1; b = -2; c = +20;
Δ = b2-4ac
Δ = -22-4·1·20
Δ = -76
Delta is less than zero, so there is no solution for the equation
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