X2+(2x+11)2=(3x+1)2

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Solution for X2+(2x+11)2=(3x+1)2 equation: 



X2+(2X+11)2=(3X+1)2

We move all terms to the left:

X2+(2X+11)2-((3X+1)2)=0

We add all the numbers together, and all the variables

X^2+(2X+11)2-((3X+1)2)=0

We multiply parentheses

X^2+4X-((3X+1)2)+22=0



We calculate terms in parentheses: -((3X+1)2), so:

(3X+1)2

We multiply parentheses

6X+2

Back to the equation:

-(6X+2)



We get rid of parentheses

X^2+4X-6X-2+22=0

We add all the numbers together, and all the variables

X^2-2X+20=0

a = 1; b = -2; c = +20;
Δ = b2-4ac
Δ = -22-4·1·20
Δ = -76
Delta is less than zero, so there is no solution for the equation

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