X2+(y+4)2=7

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Solution for X2+(y+4)2=7 equation: 



X2+(X+4)2=7

We move all terms to the left:

X2+(X+4)2-(7)=0

We add all the numbers together, and all the variables

X^2+(X+4)2-7=0

We multiply parentheses

X^2+2X+8-7=0

We add all the numbers together, and all the variables

X^2+2X+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{-2}{2}=-1$

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