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X2+100X-9600=0
We add all the numbers together, and all the variables
X^2+100X-9600=0
a = 1; b = 100; c = -9600;
Δ = b2-4ac
Δ = 1002-4·1·(-9600)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{48400}=220$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-220}{2*1}=\frac{-320}{2} =-160 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+220}{2*1}=\frac{120}{2} =60 $
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