X2+10x+24=(x+4)

Solution for X2+10x+24=(x+4) equation:

X2+10X+24=(X+4)

We move all terms to the left:

X2+10X+24-((X+4))=0

We add all the numbers together, and all the variables

X^2+10X-((X+4))+24=0


We calculate terms in parentheses: -((X+4)), so:

(X+4)

We get rid of parentheses

X+4

Back to the equation:

-(X+4)


We get rid of parentheses

X^2+10X-X-4+24=0

We add all the numbers together, and all the variables

X^2+9X+20=0

a = 1; b = 9; c = +20;
Δ = b2-4ac
Δ = 92-4·1·20
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*1}=\frac{-10}{2}
=-5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*1}=\frac{-8}{2}
=-4
$