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X2+10X-360=0
We add all the numbers together, and all the variables
X^2+10X-360=0
a = 1; b = 10; c = -360;
Δ = b2-4ac
Δ = 102-4·1·(-360)
Δ = 1540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1540}=\sqrt{4*385}=\sqrt{4}*\sqrt{385}=2\sqrt{385}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{385}}{2*1}=\frac{-10-2\sqrt{385}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{385}}{2*1}=\frac{-10+2\sqrt{385}}{2} $
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