X2+10x-5600=0

Solution for X2+10x-5600=0 equation:

X2+10X-5600=0

We add all the numbers together, and all the variables

X^2+10X-5600=0

a = 1; b = 10; c = -5600;
Δ = b2-4ac
Δ = 102-4·1·(-5600)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-150}{2*1}=\frac{-160}{2}
=-80
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+150}{2*1}=\frac{140}{2}
=70
$