X2+10x-63=0

Solution for X2+10x-63=0 equation:

X2+10X-63=0

We add all the numbers together, and all the variables

X^2+10X-63=0

a = 1; b = 10; c = -63;
Δ = b2-4ac
Δ = 102-4·1·(-63)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-4\sqrt{22}}{2*1}=\frac{-10-4\sqrt{22}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+4\sqrt{22}}{2*1}=\frac{-10+4\sqrt{22}}{2}
$