X2+12=x2+3x-6

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Solution for X2+12=x2+3x-6 equation: 



X2+12=X2+3X-6

We move all terms to the left:

X2+12-(X2+3X-6)=0

We add all the numbers together, and all the variables

-(+X^2+3X-6)+X2+12=0

We add all the numbers together, and all the variables

X^2-(+X^2+3X-6)+12=0

We get rid of parentheses

X^2-X^2-3X+6+12=0

We add all the numbers together, and all the variables

-3X+18=0

We move all terms containing X to the left, all other terms to the right

-3X=-18

X=-18/-3

X=+6

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