X2+14x-5=0

Solution for X2+14x-5=0 equation:

X2+14X-5=0

We add all the numbers together, and all the variables

X^2+14X-5=0

a = 1; b = 14; c = -5;
Δ = b2-4ac
Δ = 142-4·1·(-5)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6\sqrt{6}}{2*1}=\frac{-14-6\sqrt{6}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6\sqrt{6}}{2*1}=\frac{-14+6\sqrt{6}}{2}
$