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X2+14X-98=0
We add all the numbers together, and all the variables
X^2+14X-98=0
a = 1; b = 14; c = -98;
Δ = b2-4ac
Δ = 142-4·1·(-98)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{3}}{2*1}=\frac{-14-14\sqrt{3}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{3}}{2*1}=\frac{-14+14\sqrt{3}}{2} $
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