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X2+15X+20=0
We add all the numbers together, and all the variables
X^2+15X+20=0
a = 1; b = 15; c = +20;
Δ = b2-4ac
Δ = 152-4·1·20
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{145}}{2*1}=\frac{-15-\sqrt{145}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{145}}{2*1}=\frac{-15+\sqrt{145}}{2} $
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