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X2+15X-800=0
We add all the numbers together, and all the variables
X^2+15X-800=0
a = 1; b = 15; c = -800;
Δ = b2-4ac
Δ = 152-4·1·(-800)
Δ = 3425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3425}=\sqrt{25*137}=\sqrt{25}*\sqrt{137}=5\sqrt{137}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{137}}{2*1}=\frac{-15-5\sqrt{137}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{137}}{2*1}=\frac{-15+5\sqrt{137}}{2} $
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