X2+16x+12=7X+4

Solution for X2+16x+12=7X+4 equation:

X2+16X+12=7X+4

We move all terms to the left:

X2+16X+12-(7X+4)=0

We add all the numbers together, and all the variables

X^2+16X-(7X+4)+12=0

We get rid of parentheses

X^2+16X-7X-4+12=0

We add all the numbers together, and all the variables

X^2+9X+8=0

a = 1; b = 9; c = +8;
Δ = b2-4ac
Δ = 92-4·1·8
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-7}{2*1}=\frac{-16}{2}
=-8
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+7}{2*1}=\frac{-2}{2}
=-1
$