X2+16x+23=0

Solution for X2+16x+23=0 equation:

X2+16X+23=0

We add all the numbers together, and all the variables

X^2+16X+23=0

a = 1; b = 16; c = +23;
Δ = b2-4ac
Δ = 162-4·1·23
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{41}}{2*1}=\frac{-16-2\sqrt{41}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{41}}{2*1}=\frac{-16+2\sqrt{41}}{2}
$