X2+16x-520=0

Solution for X2+16x-520=0 equation:

X2+16X-520=0

We add all the numbers together, and all the variables

X^2+16X-520=0

a = 1; b = 16; c = -520;
Δ = b2-4ac
Δ = 162-4·1·(-520)
Δ = 2336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2336}=\sqrt{16*146}=\sqrt{16}*\sqrt{146}=4\sqrt{146}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{146}}{2*1}=\frac{-16-4\sqrt{146}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{146}}{2*1}=\frac{-16+4\sqrt{146}}{2}
$