X2+18x-9=0

Solution for X2+18x-9=0 equation:

X2+18X-9=0

We add all the numbers together, and all the variables

X^2+18X-9=0

a = 1; b = 18; c = -9;
Δ = b2-4ac
Δ = 182-4·1·(-9)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{10}}{2*1}=\frac{-18-6\sqrt{10}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{10}}{2*1}=\frac{-18+6\sqrt{10}}{2}
$