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X2+19x+60=0

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Solution for X2+19x+60=0 equation:



X2+19X+60=0
We add all the numbers together, and all the variables
X^2+19X+60=0
a = 1; b = 19; c = +60;
Δ = b2-4ac
Δ = 192-4·1·60
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
X_{1}=\frac{-b-\sqrt{\Delta}}{2a}
X_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{121}=11
X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-11}{2*1}=\frac{-30}{2} =-15
X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+11}{2*1}=\frac{-8}{2} =-4

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