X2+19x+8=0

Solution for X2+19x+8=0 equation:

X2+19X+8=0

We add all the numbers together, and all the variables

X^2+19X+8=0

a = 1; b = 19; c = +8;
Δ = b2-4ac
Δ = 192-4·1·8
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{329}}{2*1}=\frac{-19-\sqrt{329}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{329}}{2*1}=\frac{-19+\sqrt{329}}{2}
$