X2+19x-92=0

Solution for X2+19x-92=0 equation:

X2+19X-92=0

We add all the numbers together, and all the variables

X^2+19X-92=0

a = 1; b = 19; c = -92;
Δ = b2-4ac
Δ = 192-4·1·(-92)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-27}{2*1}=\frac{-46}{2}
=-23
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+27}{2*1}=\frac{8}{2}
=4
$