X2+1=10x-8

Solution for X2+1=10x-8 equation:

X2+1=10X-8

We move all terms to the left:

X2+1-(10X-8)=0

We add all the numbers together, and all the variables

X^2-(10X-8)+1=0

We get rid of parentheses

X^2-10X+8+1=0

We add all the numbers together, and all the variables

X^2-10X+9=0

a = 1; b = -10; c = +9;
Δ = b2-4ac
Δ = -102-4·1·9
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-8}{2*1}=\frac{2}{2}
=1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+8}{2*1}=\frac{18}{2}
=9
$